If you were at 13.0 : 1 and added 5% on a 4 injector bike (no upper injectors) it should bring you to about 12.2 : 1Just wondering ......
if I were increased 5 points in fuel over a certain rom range what would the a/f be on a dyno??
New fuel delivery rate = Old fuel delivery rate x (New PC correction factor / Old PC correction factor)
For expression as an air/fuel ratio you have to flip this upside down
New air/fuel ratio = Old air/fuel ratio x (Old PC correction factor / New PC correction factor)
The correction factor is 1 + whatever the number in the cell is divided by 100
e.g. if you have "5" in a particular cell then the correction factor is 1.05, and if you have "-10" in a particular factor then the correction factor is 0.9
If you had air fuel ratio 12.0 originally with no power commander, and you apply "-10" in that cell, then effectively the old correction factor was 1, so the new air/fuel ratio will be 12.0 x (1.0 / 0.9) = 13.3...
All of this is making an assumption that the fuel injectors have a delivery rate that is linear with injector duration (it should be very close unless you have a restriction in the system somewhere) and that your air/fuel ratio meter is displaying accurately and you are not going outside of the range in which it displays correctly (which is not guaranteed ...)