Kawasaki ZX-10R Forum banner

1 - 4 of 4 Posts

·
Registered
Joined
·
233 Posts
Discussion Starter #1
Ok, ready for this one? How is engine displacement figured out? Is it the volume of one cylinder w/ piston at dead bottom x #of cylinders in engine (in wich case we don't really have a 998cc bike)...or is it the total volume of all cylinders w/ the pistons at their given position at any point in the crank cycle (in wich case a 4 cylinder liter bike would have cylinders larger than 250cc each)...or am I completely off the mark?
 

·
Still here
Joined
·
9,059 Posts
(Bore X stroke of each) X number of Cyls.

998 divided by 4 = 249.5 cc volume each cylinder could hold at bottom dead center basically.

OKAY now you've got me thinking


76mm bore X 55stroke in that bore.
Has to be in the conversion to cubic centimeters- I hate math
 

·
Registered
Joined
·
536 Posts
You need to use the formula for the volume of a cylinder. For the example you gave, converting to centimeters, the diameter of the bore is 7.6 cm, the radius is half that, 3.8 cm, and the height is 5.5 cm. Therefore,
 

Attachments

·
Hillbillie Mod
Joined
·
20,155 Posts
Cryptoman said:
You need to use the formula for the volume of a cylinder. For the example you gave, converting to centimeters, the diameter of the bore is 7.6 cm, the radius is half that, 3.8 cm, and the height is 5.5 cm. Therefore,
:shady: :idea: :mrgreen:
 
1 - 4 of 4 Posts
Top